$$2\cot4x = \cot2x \tan2x$$ Thank you in advance Thank you for the comments and hints I got an answer after many tries ;) Below is my answer Thank you $2cot4x = cot2x tan2x$ $2\frac{1}{tan 4x} = cot2x tan2x$ $2\frac{1}{\frac{2 tan 2x}{1 tan^2 2x}} = cot2x tan2x$ $2\frac{1 tan^2 2x}{2 tan 2x} = cot2x tan2x$So sec^2 (x)=1tan^2 (x) This is one of the three Pythagorean identities in trigonometry, but if you don't recognize it, try converting to sines and cosines 1/cos^2 (x)=1sin^2 (x)/cos^2 (x) Now, multiply each term by cos^2 (x) to get 1=cos^2 (x) sin^2Found 2 solutions by ewatrrr, MathLover1 Answer by ewatrrr () ( Show Source ) You can put this solution on YOUR website!
Answered 8 In Parts A To E Simplify The Bartleby