$$2\cot4x = \cot2x \tan2x$$ Thank you in advance Thank you for the comments and hints I got an answer after many tries ;) Below is my answer Thank you $2cot4x = cot2x tan2x$ $2\frac{1}{tan 4x} = cot2x tan2x$ $2\frac{1}{\frac{2 tan 2x}{1 tan^2 2x}} = cot2x tan2x$ $2\frac{1 tan^2 2x}{2 tan 2x} = cot2x tan2x$So sec^2 (x)=1tan^2 (x) This is one of the three Pythagorean identities in trigonometry, but if you don't recognize it, try converting to sines and cosines 1/cos^2 (x)=1sin^2 (x)/cos^2 (x) Now, multiply each term by cos^2 (x) to get 1=cos^2 (x) sin^2Found 2 solutions by ewatrrr, MathLover1 Answer by ewatrrr () ( Show Source ) You can put this solution on YOUR website!
Answered 8 In Parts A To E Simplify The Bartleby
1-tan^2x/1-cot^2x=1-sec^2x
1-tan^2x/1-cot^2x=1-sec^2x-About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How works Test new features Press Copyright Contact us Creators Calculus 2, integral of (1 tan^2x) sec^2x, integral of cos(2x) Hi simplifying the following (sec^2x csc^2x) (tan^2x cot^2x) tan^2x = sec^2x 1 cot^2x = csc^2x 1 (sec^2x csc^2x) (sec^2x 1 csc^2x 1)= 2click here👆to get an answer to your question ️ if sec x sec^ 2x = 1 then the value of tan^ 8 tan^ 4 2tan^ 2x 1 will be equal tox = 1287 2 = the period of the function is the
$\begingroup$ Well, if your instructor insisted that you do this by calling in the doubleangle formula, then I would replace my second paragraph with a criticism of the instructor for making things unnecessarily difficult Indeed, if the question had been to solve $\tan(9x/2)=1$, it would have been frustratingly difficult to use the ninefold angle formula and the halfangle formulas,Trigo Identities We should know that 1 (tan^2x)=sec^2x also 1 (cot^2x)=csc^2x Substituting these identities to the eqn (tan^2x) (cot^2x)= (sec 1 tan2x= 1sin2x/cos2x Find common denominator which is cos2x cos2x/cos2x sin2x/cos2x (cos2x sin2x)/cos2x 1cot2x = 1 cos2x/sin2x Common denominator is sin2x sin2x/sin2x cos2x/sin2x ( sin2x cos2x)/sin2x 1/(cosx2 sin2x)/cos2x 1/( sin2x cos2x)/sin2x
See the answer See the answer See the answer done loading Show transcribed image text Expert Answer Who are the experts?Giải phương trình 1, \(2\tan^2x3\tan x 2\cot^2x3\cot x 2=0\) 2, \(\cos^23x\cos2x\cos^2x=0\) 3, \(\cos^22x2\left(\cos x \sin x\right)^23\sin2x 1=0\) 4, \(1Sin(a/2)= square root of (1cos(a))/2 Since the radical is on the right side of the equation , switch the sides so it is on the left side of the equation To remove the radical on the left side of the equation , square both sides of the equation
Mylove mylove Mathematics High School answered Cot^2xtan^2x=1 for all values of x true or false?Hi Simplifying the following (sec^2x csc^2x) (tan^2x cot^2x) tan^2x = sec^2x 1 cot^2x = csc^2x 1 (sec^2x csc^2x) (sec^2x 1 csc^2x 1)= 2Chứng minh đẳng thức (tan^3x/sin^2x)(1/sinxcosx) (cot^3x/cos^2x)=tan^3x cot^3x
A=√sin2x(1 cotx) cos2x(1 tanx) B=sin^2xtan^2x/cos^2xcot^2x CẦN GẤP ẠAnswers Click here to see ALL problems on Trigonometrybasics Question tan^2xcot^2x=sec^2xcsc^2x Answer by jojo (1513) ( Show Source ) You can put this solution on YOUR website!Answers pineapplepizaaaaa Here for a good time of free question carrieaj08 no association stepbystep explanation
Here, the problem is (cot^2 x 1)/ (tan^2 x 1) so cotx = 1/tanx by putting the value of cotx in above equation the simplified equation is (1 tan^2 x)/ (tan^2 x 1) (tan^2 x) (tan^2 x 1)/ (tan^2 x 1) (tan^2 x) 1/tan^2 x cot^2 x that should be the(tan x cot x)^2 = tan^2 x 2 tan x cot x = tan^2x cot^2x = (tan^2x 1) (cot^2 ) = This problem has been solved!Question prove the following identity cos2A = 2cos^2A 1 Answer by sarah_adam (1) ( Show Source ) You can put this solution on YOUR website!
Cos2A = Cos (AA) we know the formula for Cos (AB)=CosACosBSinASinB therefore Cos (AA)= CosACosA SinASinA = Cos^2A Sin^2A WE also know that Cos^2A Sin^2A = 1Prove each identity a) 1cos^2x=tan^2xcos^2x b) cos^2x 2sin^2x1 = sin^2x I also tried a question on my own tan^2x = (1 – cos^2x)/cos^2x RS= sin^2x/cos^2x I know that the Pythagorean for that is sin^2x cos^2x That's all I could do Trigonometry Express sec2x in terms of tanx and secx I know you have to sec(2x) = 1/cos(2x) = 1/(cos²x sin²x) But how do you split that Like how to simplify that?
Find an answer to your question Cot^2xtan^2x=1 for all values of x true or false?Cot^2xcsc^2x=1 for all values of x true or falsse Question Cot^2xcsc^2x=1 for all values of x true or falsseExperts are tested by Chegg as specialists in their subject area We review their content and use
Chứng minh biểu thức sau độc lập với x \(\frac{\tan ^2x\cos ^2x}{\sin ^2x}\frac{\cot ^2x\sin ^2x}{\cos ^2x}\)Answered 2 years ago Author has 367 answers and 1508K answer views Start by simplifying cot^2 x 1 = cos^2 x/sin^2 x 1 = (cos^2x sin^2x)/sin^2 x = cos2x/sin^2x Next step, simplify tan2x * cot^2 xtan2x = tan2x (cot^2x1)=tan2x*cos2x/sin^2 x = sin 2x/sin^2 x1) sin3x = 0 2) cos 2 5x = 0 3) tan (x 15 o) = 3tan (x 15 o) 4) cos x cos 2x cos 3x = 0 5) sin 2x sin 4x sin 6x = 0 6) tan x tan 2x tan xtan 2x = 1 7) tan x tan 2x tan 3x = tan xtan 2xtan 3x 8) cot 2 x 3 sin x 3 sin x 3 = 0 Lớp 11 Toán
Answer (2) 2 Solution (cot x – tan x)/ cot 2x = tan 2x (1/tan x) – tan x = tan 2x (1 – tan 2 x)/tan x = tan 2x (1 – tan 2 x)/ 2 tan x 2 Using the formula tan 2A = 2 tan A/ (1 – tan 2 A) = 2 tan 2x (1/tan 2x) = 2Cosx(tan^2x1)=secx Answer by jim_thompson5910() (Show Source) You can put this solution on YOUR website! Cot^2xtan^2x=1 for all values of x true or false?
Trigonometric Simplification Calculator \square!Verify the Identity cot (x)^2 (sec (x)^21)=1 cot2 (x) (sec2 (x) − 1) = 1 cot 2 ( x) ( sec 2 ( x) 1) = 1 Start on the left side cot2(x)(sec2(x)−1) cot 2 ( x) ( sec 2 ( x) 1) Apply pythagorean identity cot2(x)tan2(x) cot 2 ( x) tan 2 ( x) Convert to sines and cosines Tap for more steps Write cot ( x) cot ( x) in sines and cosinesFree math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutor
This is what I've got so far sin = 1/csc tan = 1/cot 1cot2(x) = csc2(x) 1/1cot2(x) = 1/csc2(x) trig For each expression in column I, choose the expression from column II to complete an identity Column I Column II 1 tanxcosx A sin^2x/cos^2x 2 sec^2x1 B 1/sec^2x 3 sec x/cscx C sin(x) 4 1sin^2x Dcsc^2xcot^2xsin^2x 5 cos^2 x E Prove the following identities $$(\sec^2 x \tan^2x)(\csc^2 x \cot^2x) = 1 2 \sec^2x \csc^2 x \tag i$$ $$\frac{\cos x}{1\tan x} \frac{\sin x}{1\cot x} = \sinMath please help quick Which of the following are identities?
1 cos ( x) − cos ( x) 1 sin ( x) = tan ( x) Go!Tan2x Formula Trigonometric Formulas like Sin 2x, Cos 2x, Tan 2x are known as double angle formulas because these formulas have double angles in their trigonometric functions Let's discuss Tan2x Formula Tan2x Formula = 2 tan x 1 − t a n 2 xFree math lessons and math homework help from basic math to algebra, geometry andFind all solutions of sec^2xtan^2x=3 in the interval 0,2pi Since tan^2 = sec^2 1 you get sec^2 sec^21 = 3 2sec^2= 4 sec^2 = 2Check all that apply (Points 2) sin2x = 1 cos2x sin2x cos2x = 1 tan2x = 1 sec2x cot2x = csc2x 1 Question 4 4
Cot^2x tan^2x = 1 for all values of x False Cos2A = 2cos^2A1 for all values of x True Sin(x)=cosx for all values of x False Cos(AB)=cosAcosBsinAsinB True Trigonometric equations and trigonometric identities are the same thing False _____cos B = 1/2 cos(AB)cos (AB) cos AProve each identity a) 1cos^2x=tan^2xcos^2x b) cos^2x 2sin^2x1 = sin^2x I also tried a question on my own tan^2x = (1 – cos^2x)/cos^2x RS= sin^2x/cos^2x I know that the Pythagorean for that is sin^2x cos^2x That's all I could do trig tan^2 x1=sec^2x So to get 1 on the other side of the equal sign wouldn't it be sec^2xtan^2x=1?
Answer by stanbon (757) ( Show Source ) You can put this solution on YOUR website! Find an answer to your question If 2tanx/ (1tan^2x) = 1, then x can equal ____ Check all that apply A) x=5pi/8 npi B) x=pi/8 npi C) x=3pi/8 npi D) x=7p tan^2x (1tan^2x)/(1cot^2x) 1) First, notice that both the numerator and denominator are Pythagorean Identities Proceed to change them sec^2x/csc^2x 2) Turn into sine and cosine Then multiply
This question was just answered and I'm not sure if this is the same person or not If so, please let me know where you're stuck andSimplify (tan (2x))/ (1cot (2x)) tan (2x) 1 − cot(2x) tan ( 2 x) 1 cot ( 2 x) Nothing further can be done with this topic Please check the expression entered or try another topicGet stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!
0 件のコメント:
コメントを投稿